Charles K.Alexander,Sadiku chaper 5 problem 5.31

 

Solution:

Redraw the circuit

At node v1 ,                   (12-v1)/3 = (v1-vo)/6 + (v1-vo)/12  

                                         7v1 -3vo = 48  ………………………..(1)

At node vo ,                   (v1-vo)/6  =  vo/6

                                          2vo = v1  ………………………………..(2)

                     

Now from equation (1),

            7v1 -3vo = 48

           14vo -3vo = 48

           Vo = 4.364 v

     Ix = 4.36 /6k

        = 0.7273 mA           (Ans)